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#1 (permalink) | |||
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Bad Boy For Life
Last Online: Today 06:06 PM Join Date: Nov 2005
Location: Shafkat
Posts: 3,407
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A good poker player should think about what their opponent is thinking. A great poker player should think about what what their opponent thinks they're thinking, and an excellent poker player should think about what their opponent thinks they think their opponent is thinking. You need to know what information your opponent has and what information they think you have, in order to make good decisions, and understand your opponent's decisions. I came across this question about a game which should test how well people can empathise with the information of others.
Ann and Bob are told that a positive integer, x, has been chosen. One of them has x written on their forehead and one has x+1 written on their forehead. Obviously they can see the number on their partner's head but not the number on their own head. Ann has 4 written on her forehead, and Bob has 5 written on his forehead. They are asked in turn what the number written on their own forehead is. They can only answer with the correct answer (i.e. they know) or say that they don't know. (no guesses) The dialogue goes like this: Interviewer: Ann, what is your number? Ann: I don't know. Interviewer: Bob, what is your number? Bob: I don't know. Interviewer: Ann, what is your number? Ann: I don't know. Interviewer: Bob, what is your number? Bob: My number is 5. How did Bob know what his number was? No stupid answers like him being telepathic, seeing the reflection in Ann's eyes, absorbing the ink into his brain, or calculating the weight of ink required to write his number in conjunction with seeing the arm movements of whoever wrote it on his head. He knows the answer purely from the information he has gained from Ann, the number on her forehead, knowledge of the rules and knowledge that Ann knows the rules. It took me pretty long to get the answer, but it still feels pretty weird how he could know. The vast majority of people (myself included) would not be as rational as Ann and Bob. They are perfectly rational agents. I'll give 5000 vChips to anybody who gets it.
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#2 (permalink) |
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outdrawn on every street
Last Online: Today 08:16 PM Join Date: Mar 2006
Location: Cheltenham
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0 + 1 = 1
1 + 1 = 2 2 + 1 = 3 3 + 1 = 4 therfore 4 + 1 = 5 |
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#3 (permalink) | |||
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Bad Boy For Life
Last Online: Today 06:06 PM Join Date: Nov 2005
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There's no real method to that answer is there? If it was just a case of adding up the times people had said they didn't know +1, why didn't he just say 2 after she said she didn't know the first time?
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#4 (permalink) |
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Rank: Player
Last Online: 28th August 2007 10:37 PM Join Date: Sep 2006
Posts: 78
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Intresting, maybe Bob had worked out that ann (like me) hadn`t got a clue what a positive integer was so,whatever No she could see on his head would mean little or nothing to her or the number she could see on his head wasn`t a positive integer but, Bob new exactly what a positive integer was and he new that Ann had a positive
integer the No 4 on her head so after she had ansewered several times I dont know he assumed the No on his own head may not be a positive integer therefore Ann had the positive integer on her head and he had the positive integer in this case 4 +1 on his head which even a maths Dodo like myself could work out was 5.Sounds plausable to me after a few glasses of Vino any way. |
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#5 (permalink) |
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Rank: Untouchable
Last Online: Today 09:04 PM Join Date: Nov 2005
Location: Bristol
Posts: 2,742
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Ann sees 5: therefore her card is 4 or 6
Bob sees 4 therefore his card is 3 or 5 If ann thinks her card is a 4 then she thinks bob must think her card is a 3 or 5 If ann thinks her card is a 6 then she thinks bob must think her card is a 5 or 7 So the common denominator in anns thinking what he is thinking is the number 5 there for bob must have a 5 which he does!! If bob thinks his card is a 3 then he thinks that ann must think her card is a 4 or 2 If bob thinks his card is a 5 then he thinks that ann must think her card is a 6 or 4 So the common denominator in bobs thinking what she is thinking is the number 4 there for bob must have a 5!! Do you know what i cant be arsed any more..... i was sat happily working it out and now i need slepp - so i will post this and finish it tomorrow!! |
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#6 (permalink) | |||
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Bad Boy For Life
Last Online: Today 06:06 PM Join Date: Nov 2005
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OK here's the first step of the process. If Bob can see that Ann has 4 on her head, then he knows that he either has 3 or 5 on his head right? Because he doesn't know if he has the x or the x+1 card.
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#7 (permalink) | ||||
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Bad Boy For Life
Last Online: Today 06:06 PM Join Date: Nov 2005
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Same with your theory about Bob's number. But you got pretty close to sussing out some stuff.
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#8 (permalink) | ||
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Adopt a donk
Last Online: Today 04:52 PM Join Date: Dec 2003
Location: Bristol
Posts: 4,030
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Interviewer: Ann, what is your number?
Ann: I don't know. - Ann isn't sure if her number is 4 or 6 Interviewer: Bob, what is your number? Bob: I don't know. - Bob isn't sure if his number is 3 or 5 Interviewer: Ann, what is your number? Ann: I don't know. Interviewer: Bob, what is your number? Bob: My number is 5. - Bob knows that Ann has a 4 on her head, and he now knows that she is torn between thinking if she has a 4 or 6 on her head. As he can see that Ann doesn't have a 6 on her head, he can therefore deduce that he must have a 5 on his head. Beeejezus.. I've reworded that about 6 times, but still can't verbalise how I've worked it out in my head... Not sure if that's right or not, but I'd guess it's getting close
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#9 (permalink) |
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Rank: Beginner
Last Online: 12th October 2006 03:25 AM Join Date: Oct 2006
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Ok, in final stage in Bob's opinion x=3 or 4. If x=3, then Ann would think that x=2 or 3. But Ann can't think that x=2 as if she did then she would think that Ben thought that x=1 or 2. Here x=1 implies that Ann thinks that her number is 2, but that isnt the case. x=2 implies that Ben thinks he has a solution but he hasn't offered one yet. So if x=3 then Ann would think that x=3 but she hasn't offered a solution yet. So x=4 and his own number is 5.
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#10 (permalink) | |
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outdrawn on every street
Last Online: Today 08:16 PM Join Date: Mar 2006
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I will give 10,000 vchips to anyone who deletes this nonsense!! |
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